ASM and a LDIVU example

[lilltroll]

If you read the ASM manual ver. 9.9 you will probably get confused - until it's updated.

Reading the The XMOS XS1 Architecture describes the LDIVU operation as

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LDIVU d, e, x, y, v

The XS1 Assembly Language Manual seems to show two incorrect ways of writing it

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LDIVU  d,x,y,e,v    ldivu  d, e, v, x, y

For the moments it's seems to be several errors explaining the operands in the ASM manual.
The correct notation is found in the XS1 architecture.

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#include <stdio.h>

int main(){
	unsigned int Xh=0,Xl=31;
	unsigned int y=5;
	unsigned int Q;
	unsigned int R;
	
	asm("LDIVU %0,%1,%2,%3,%4" : "=r"(Q) , "=r"(R) : "r"(Xh) , "r"(Xl) ,"r"(y)); 
	printf("Q=%u, R=%u",Q,R);
}

Gives the following result on the console:
Q=6, R=1

31/5 = 6 + 1/5
Q is the Quotent, R is the reminder and the operation is (uint_64) X/(uint_32) y where X is expressed as 2 32-bits number Xhigh and Xlow.

Thus its:
LDIVU Quotent,Reminder,Xhigh,Xlow,Y

[larry]

Thanks for pointing this out

The architecture manual is indeed correct and doesn't match the result you currently get in assembly as per your experiment. However, that will change in the next tools release - the LDIVU syntax will only be allowed in so called architectural mode, which exactly matches the architecture manual.

For example, in the next tools release (10.4), your experiment would become (note the different order of arguments):

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asm(".syntax architectural\nLDIVU %0,%1,%2,%3,%4\n.syntax default" : "=r"(Q) , "=r"(R) : "r"(Xl) , "r"(y) ,"r"(Xh)); 

This is a part of a set of changes (hopefully last one) to the various forms of assembler syntax. The assembly language manual is undergoing major changes and will be merged into the Tools User Guide included in the next tools release.

We want to allow 3 different forms of syntax:

• Standard - ldivu
• Machine specific - LDIVU_l5r (currently undocumented)
• Architectural mode in-line with architecture manual - LDIVU (with .syntax directive)

This will be detailed in the 10.4 Tools User Guide.